Question

Determine the volume of ethyl alcohol required to prepare 250 mL of a 45% by volume solution.

Answer 1

Let the volume of alcohol taken = x mL.

Volume percent = Volume of alcohol/ volume of solution* 100.

Or 45= $\frac{x}{250}$ or X (i.e. volume of ethanol mixed).

= $\frac{250}{100}\times 45$

= 112.5 mL.