What mass of water is consumed by the reaction of 9.04 g of carbon dioxide?
CO2 + H2O = H2CO3
Moles of CO2 present;
9.04g × 1mol/44g = 0.205
Mass of H2O consumed;
0.205 moles CO2 × 1mol H2O/mol CO2 × 18g/mol H2O = 3.69g
= 3.7g
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