Question

What mass of water is consumed by the reaction of 9.04 g of carbon dioxide?

Answer 1

CO2 + H2O = H2CO3

Moles of CO2 present;

9.04g × 1mol/44g = 0.205

Mass of H2O consumed;

0.205 moles CO2 × 1mol H2O/mol CO2 × 18g/mol H2O = 3.69g

= 3.7g