Question #303661

Calculate the concentration of C6H5NH3+ and Cl− in a 0.230 M C6H5NH3Cl solution.  


1
Expert's answer
2022-02-28T11:03:57-0500

The salt ionises completely as follows


C6H5NH3Cl(aq)→C6H5NH3++Cl−C_6H_5NH_3Cl_{(aq)}\to C_6H_5NH_3^++Cl^-


Therefore the concentration are:

[C6H5NH3+]=0.230M[C_6H_5NH_3^+]=0.230M


[Cl−]=0.230M[Cl^-]=0.230M







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