Calculate the concentration of C6H5NH3+ and Cl− in a 0.230 M C6H5NH3Cl solution.
The salt ionises completely as follows
"C_6H_5NH_3Cl_{(aq)}\\to C_6H_5NH_3^++Cl^-"
Therefore the concentration are:
"[C_6H_5NH_3^+]=0.230M"
"[Cl^-]=0.230M"
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