The boiling point of chloroform increased by 3.68 degrees C when 0.167 g of an unknown sample was dissolved in 1.00 g of chloroform (Kb = 3.63 degrees C/m). Find the molar mass of the unknown compound.
∆Tb = 3.68 °C
Kb = 3.63 °C/m
∆Tb = Kb × m = Kb × n solute / m solvent(kg) = Kb x m solute / (Mr solute x m solvent(kg))
3.68 °C = 3.63 °C kg/mol × 0.167 g × 1000 / (Mr × 1.00 g)
Mr = 164.73 g/mol
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