How many mL of water must be added to 250mL of 0.578 M CaCl2 solution to give a 0.349 M solution?
CaCl2+H2O =CaO +2HCL
Moles of CaCl2
=250×0.578=144.5 moles
Mole ratio is 1:1 so moles of water =144.5
Ml=144.5/0.349=414.04ML
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