If 4.9g of nitrogen gas is placed in a 2 L container at 31 degrees, what is the pressure in the container?
In Kelvins, 31oC = 31 + 273 = 304 K. According to the ideal gas law,
"PV=nRT"
"n(N_2)=4.9\\ g\\times\\frac{1\\ mol}{28.01\\ g}=0.175\\ mol"
"R=0.08206\\frac{L\\cdot{atm}}{mol\\cdot{K}}" (constant)
"P=\\frac{nRT}{V}=\\frac{0.175\\ mol\\times0.08206\\frac{L\\cdot{atm}}{mol\\cdot{K}}\\times304\\ K}{2\\ L}=2.18\\ atm"
Answer: 2.18 atm
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