Question

6.80 g of soduim chloride are added to 265 g of water. find the mole fraction of thesoduim chloride and water in the solutiom

Answer 1

Molar mass of NaCl$=58.44g/mol$

Molar mass of Water $=18.02g/mol$

Moles of NaCl$=\frac{6.80}{58.44}=0.1164$

Moles of H₂O $=\frac{265}{18.02}=14.7059$

Total moles $=14.8223$

Mole fraction of H₂O$=\frac{14.7059}{14.8223}=0.9922$

Mole fraction of NaCl $=1-0.9922$

$=0.0078$