Question

For a solution of pH 5.0 at 25°C, calculate [H+] and [OH-].

Accepted Answer

WE KNOW THAT PH+POH=14 SO, POH=14−PH=14−5=9 ALSO, POH=−LOG [OH−]=9 HENCE, [OH−]=1×10−9 M THEREFORE, THE HYDROXIDE ION CONCENTRATION OF THE SOLUTION IS 10−9 M.

Question #301494

Expert's answer

We know that pH+pOH=14
So, pOH=14−pH=14−5=9
Also, pOH=−log [OH−]=9
Hence, [OH−]=1×10−9 M
Therefore, the hydroxide ion concentration of the solution is 10−9 M.

Question #301494

Expert's answer

We know that pH+pOH=14So, pOH=14−pH=14−5=9Also, pOH=−log [OH−]=9Hence, [OH−]=1×10−9 MTherefore, the hydroxide ion concentration of the solution is 10−9 M.

We know that pH+pOH=14
So, pOH=14−pH=14−5=9
Also, pOH=−log [OH−]=9
Hence, [OH−]=1×10−9 M
Therefore, the hydroxide ion concentration of the solution is 10−9 M.