How many total atoms are in 0.510 g of P2O5?
Molar mass of P2O5 =141.9=141.9=141.9
Avogadro's constant =6.022×1023=6.022×10^{23}=6.022×1023
Number of atoms in one molecule=7=7=7
Total atoms
0.510141.9×6.022×1023×7\frac{0.510}{141.9}×6.022×10^{23}×7141.90.510×6.022×1023×7
=1.515×1022=1.515×10^{22}=1.515×1022 Atoms
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