A beaker contains 45.5 mL of carbon tetrachloride (CCl4, density is 1.59 g/mL).
Determine how many molecules of carbon tetrachloride are in the beaker.
Mass =45.5×1.59==45.5×1.59==45.5×1.59= 72.345g72.345g72.345g
Molar mass of CCl4=153.82g/mol_4=153.82g/mol4=153.82g/mol
Avogadro's constant=6.022×1023=6.022×10^{23}=6.022×1023
Number of molecules=72.345153.82×6.022×1023=\frac{72.345}{153.82}×6.022×10^{23}=153.8272.345×6.022×1023
=2.83×1023=2.83×10^{23}=2.83×1023 Molecules
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