Determine the molarity of each of the following solutions:
a. 2.34 mol KCl in 2.300 L of solution
b. 0.56 g H2SO4 in 2 L of solution
c. 20.45 g Al(NO3)3 in 2000 mL of solution
a) molarity =2.342.300=1.017M=\frac{2.34}{2.300}=1.017M=2.3002.34=1.017M
b) molarity =0.5698×2=0.0029M=\frac{0.56}{98×2}=0.0029M=98×20.56=0.0029M
c) molarity =20.45223×2==\frac{20.45}{223×2}==223×220.45= 0.046M
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