Question

1. The reaction of peroxydisulfate ion (S2O2-8) with iodine ion (I-) is

S2O82-(aq)+3I-(aq)2SO42-(aq)+I3-(aq)

Answer 1

S₂O₈^2-_(aq) + 3I^-_(aq) = 2SO₄^2-_(aq) + I₃^-_(aq)

K = [SO₄^2-]²[I₃^-] / [S₂O₈^2-][I^-]³