Answer to Question #300855 in General Chemistry for Hoppie king

Question

Under the same condition of pressure Hydrogen diffuses 8 times as fast as gas Y. Calculate the relative molecular mass

Answer 1

rate for y = 1

rate for H2 = 8

$\frac{rH_2}{rY}=\sqrt{\frac{MMY}{MMH_2}}$

$\frac{8}{1}=\sqrt\frac{MMY}{MMH_2}$

$8^2=\frac{MMY}{2}$

$MMY=64×2=128g/mol$

Relative molecular mass= 128g/mol