An empty 1.0 L was filled with 5.0 moles of oxygen and 4.0 moles of nitrogen monoxide. If the amount of NO2 at equilibrium is 1.5 moles, calculate the equilibrium constant, Kc.
2NO(g) + O2(g) ⇌ 2 NO2 (g)
Kc=[NO2]2[NO]2[O2]K_c=\frac{[NO_2]^2}{[NO]^2[O_2]}Kc=[NO]2[O2][NO2]2
2NOg+O2(g)⇌2NO2I450C−1.5−0.751.5E2.54.251.5\begin{matrix} & 2NO_{g}&+&O_{2(g)}&\rightleftharpoons&2NO_2\\I&4&&5&&0 \\C&-1.5&&-0.75&&1.5\\E&2.5&&4.25&&1.5 \end{matrix}ICE2NOg4−1.52.5+O2(g)5−0.754.25⇌2NO201.51.5
Kc=1.52(4.25)(2.5)2=0.084706K_c=\frac{1.5^2}{(4.25)(2.5)^2}=0.084706Kc=(4.25)(2.5)21.52=0.084706
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