Question

You want to create a 0.25 M Sodium Bicarbonate solution. You weigh 5.00 grams of Sodium Bicarbonate. How much water is needed?

Answer 1

Molarity (M) = no. of moles $/$ volume

molar mass of sodium bicarbonate $NaHCO_3=84$

No. of moles of sodium bicarbonate $=\frac{5}{84}=0.05952$

volume of water needed = $\frac{no. \space of \space moles}{molarity}= \frac{0.25}{0.05952}=4.2litres$