Question #299551

A solution prepared by adding 10g of an unknown non-volatile, non-electrolyte solute to 150 g of water. The Boiling point of the solution is elevated by 0.433 0C above the normal boiling point of the solvent. What is the molar mass of the unknown substance?



Expert's answer

ΔTb=kb.m.\Delta\>T_b=k_b.m.


kbk_b For water =0.515°C/M=0.515°C/M


0.433=0.515M0.433=0.515M

M=0.8407MM=0.8407M


Mass of solution in 1kg of water =1000150×10=66.67g=\frac{1000}{150}×10=66.67g


Molar mass of solute =10.8408×66.67=79.30g=\frac{1}{0.8408}×66.67=79.30g



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