Question #299551

A solution prepared by adding 10g of an unknown non-volatile, non-electrolyte solute to 150 g of water. The Boiling point of the solution is elevated by 0.433 0C above the normal boiling point of the solvent. What is the molar mass of the unknown substance?



1
Expert's answer
2022-02-19T06:53:08-0500

ΔTb=kb.m.\Delta\>T_b=k_b.m.


kbk_b For water =0.515°C/M=0.515°C/M


0.433=0.515M0.433=0.515M

M=0.8407MM=0.8407M


Mass of solution in 1kg of water =1000150×10=66.67g=\frac{1000}{150}×10=66.67g


Molar mass of solute =10.8408×66.67=79.30g=\frac{1}{0.8408}×66.67=79.30g



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