Question #299308

Determine the ratio of the electric force tonthe gravitational force between an electron and a proton when separated by a distance r.

1
Expert's answer
2022-02-19T06:55:07-0500


Mass of electron, me=9.11×1031kg=9.11×10^{-31}kg

Mass of protonmp=1.67×1027kgm_p= 1.67×10^{-27}kg


Newton Gravitational constantG=6.67×1011Nm2kg2G= 6.67×10^{-11}Nm^2kg^{-2}



Gravitational force FG=F_G=

=GMpMer2=(6.67×1011)1.67×1027×9.1×1031r2=\frac{GM_pM_e}{r^2}=(6.67×10^{-11})\>\>\frac{1.67×10^{-27}×9.1×10^{-31}}{r^2}


=1.015×1067r2=\frac{1.015×10^{-67}}{r^2}


Electric force Fe=Kqeqer2=9×109×(1.6×1019)2r2F_e=\frac{Kq_eq_e}{r^2}=\frac{9×10^9×(1.6×10^{-19})^2}{r^2}


=2.304×1028r2=\frac{2.304×10^{-28}}{r^2}



FeFq=2.27×1039\frac{F_e}{F_q}=2.27×10^{39}







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