Answer to Question #299038 in General Chemistry for Hana

Question

How many mL of 0.250 M HCI would react exactly with 30.0 mL of the 0.150 M solution of Ca(OH)2 solution? The chemical reaction involved is:

HC1(aq) + NaOH(aq) → NaCl(aq) + H2O (1)

Answer 1

Chemical reaction

2HCl +CA(OH)₂ → CaCl₂ +2H₂O.

2 mol HCl : 1Ca(OH)_2.

Given,

M=0.150 M CA(OH)₂

V=30 ml CA(OH)_2.

M = 0.250 M HCl.

V= ?

CA(OH)₂

M =M×V

=0.15×30

=4.5 mol CA(OH)₂

Therefore to find the moles in terms of HCl.

M= 4.5 mol CA(OH)₂× 2 mol HCl/ 1 mol CA(OH)₂

M= 9.0 mol HCl.

Molar HCl= mol HCl/ vol HCl.

0.250 M =9.0 mol HCl/vol HCl.

Vol HCl=9.0 mol HCl/0.250 M.

Ans=36 ml HCl