Answer to Question #298991 in General Chemistry for Madison

Question

12.755 g of a metal initially at 99.0 c are placed into 75.0g of water initially at 23 c the final temperature of the water is 24.5 c calculate the specific heat of the metal the specific heat of water is 4.184 J/g c

Answer 1

Mass of water,m=75.0g

Specific heat of water,s=4.184J/g°c

Change in temperature,∆T=24.5°c - 23.0°c

=1.5°c

Amount of heat absorbed by water= ms∆T

=75.0g×4.184 J/g°c

=470.7J

Amount of heat lost by metal is equal to the heat absorbed by water.

=-470.7J

Mass of the metal submerged,m= 12.755g

∆T=24.5°c-99.0°c

= -74.5°c

Therefore,,

Specific heat capacity of the metal:

-470.7J/(12.755g)(-74.5°c)

Ans= 0.495J/g°c.