In a biochemical assay, a chemist needs to add 2.93 g of glucose to a reaction mixture. Calculate the volume in mL of a 1.35M glucose solution she should use for the addition.
Molar mass of glucose=180.156g/mol= 180.156g/mol=180.156g/mol
V1000×1.35×180.156=2.93\frac{V}{1000}×1.35×180.156=2.931000V×1.35×180.156=2.93
V=12.05ml
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