The equilibrium constant for the reaction at 700.0 K is 0.44. What is the concentration of carbon dioxide gas (CO2) and hydrogen gas (H2), if [H2O] = 0.16 mol/L, and [CO] = 0.15 mol/L? H2O (g) + CO (g) = CO2 (g) + H2 (g)
Kc=[CO2][H2][H2O][CO]K_c=\frac{[CO_2][H_2]}{[H_2O][CO]}Kc=[H2O][CO][CO2][H2]
0.44=x.x(0.16)(0.15)0.44=\frac{x.x}{(0.16)(0.15)}0.44=(0.16)(0.15)x.x
x=0.1028Mx=0.1028Mx=0.1028M
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments