Question #297975

The equilibrium constant for the reaction at 700.0 K is 0.44. What is the concentration of carbon dioxide gas (CO2) and hydrogen gas (H2), if [H2O] = 0.16 mol/L, and [CO] = 0.15 mol/L? H2O (g) + CO (g) = CO2 (g) + H2 (g)


1
Expert's answer
2022-02-16T11:39:02-0500

Kc=[CO2][H2][H2O][CO]K_c=\frac{[CO_2][H_2]}{[H_2O][CO]}


0.44=x.x(0.16)(0.15)0.44=\frac{x.x}{(0.16)(0.15)}



x=0.1028Mx=0.1028M



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