Answer to Question #297921 in General Chemistry for Phia

Question

The osmotic pressure of 250mL of an aqueous solution containing 0.150g of the enzyme lysozyme is found to be 0.0013atm at 24.850 Calculate the molar mass of lysozyme.

Answer 1

$\pi$ = iMRT

$\pi$ - osmotic pressure (atm)

i - van't Hoff's factor

M - molar concentration of solution (mol/l)

M = m(solute)/[Mr(solute)xV(solution)]

R - ideal gas constant (0.08206 l atm mol^-1 K^-1)

T - temperature (K)

0.0013 atm = 1 x 0.150 g / [Mr(lysozyme)x0.250 l] x 0.08206 l atm mol^-1 K^-1 x (24.850 + 273.15 K)

Mr(lysozyme) = 11 286.4 g/mol