Answer to Question #297706 in General Chemistry for Christian

Question

A piece of metal with a mass of 97.6 grams was heated in a steam jacket to 94°C and then

plunged into 243.6 grams of water at 21 degrees * C causing the temperature to rise to 24 degrees * C What

is the specific heat of metal?

Answer 1

$H =mc\Delta\theta$

Heat lost by metal

$= 97.6×c × (94-24)= 6832c$

Heat gained by water

$243.6 ×4.184×(24-21)= 3057.7$

$6832c=3057.7\\x= 0.4476Jg^{-1}K^{-1}$