1. How many grams of BaCl2 should be added to 300 g H2O so that the freezing point of the solution is lowered – 8.3 0C? Assume that the BaCl2 completely dissociates in the solution.
Show Its Given, Required, Equation, Solution, Answer
∆T=iKbm.
m=∆T/iKb. = 8.3/3 x 1.86 = 1,4874552 mol/kg.
m=moles of solute/kg of solvent.
1,4874552 x 0.3 = 0,44623656.
0,44623656 x 208 = 92,8172045 g of BaCl2.
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