Question #297132

What is the change in the internal energy of a system in which 66.1 kJ of heat is transferred to the surroundings while the surroundings do 44.0 kJ of work on the system? Provide an answer that is correct to 3 significant figures. 


Expert's answer

Δu=Qw\Delta\>u=Q-w

Q=+66.1kJQ=+66.1kJ

w=(44.0kJ)w=(-44.0kJ)


    Δu=66.1(44.0)\implies\Delta\>u=66.1-(-44.0)

=110.1=110.1

=110kJ(=110kJ( 3 significant figures))






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