The superficial mass velocity is found to be 200 lb/hr.ft2. Find its
equivalent in kg/s.m2
(a) the equivalent mass velocity is 300 lb/(h*ft2) * 0.4536 kg/lb / 3600 s/h / (0.3048 m/ft)2Â =
0.4069 kg/(s*m2)
(b) By definitions:
760 mmHg = 1 atm = 101325 Pa
1 bar = 100000 Pa = 1/1.01325 atm = 760/1.01325 mmHg = 750.06 mmHg
(c) Suppose ideal gas, when:
p*V = m/M*R*T
m = 150 g,
M = 44 g/mole,
R = 8.314 J/(K*mole),
T = 5/9*(100 F - 32) + 273.15 = 310.93 K,
V = 100 cm3Â * 10-6Â m3/cm3Â = 10-4Â m3
p = 150/44*8.314*310.93/10-4Â = 88127455 Pa = 88127455 Pa / 101325 Pa/atm * 760 mmHg/atm = 661010 mmHg
Answer: pressure is 661010 mmHg
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