Answer to Question #296748 in General Chemistry for meso

Question

A balloon has a volume of 253.2 L at 2.5 atm. The volume of the balloon is decreased to 165.4 L. Determine the new pressure. *

Answer 1

The new temperature is 233 K

.

Explanation:

Charles' law states that when pressure is held constant, temperature and volume are directly proportional. The equation to use is V

1

T

1

V

2

T

2

.

Given

V

1

=

252.3

mL

×

1

L

1000

mL

=

0.2523 L

T

1

=

356 K

V

2

=

165.4

mL

×

1

L

1000

mL

=

0.1654 L

Unknown

T

2

Equation

V

1

T

1

V

2

T

2

Solution

Rearrange the equation to isolate T

2

.

T

2

=

T

1

V

2

V

1

T

2

=

(

356

K

)

×

(

0.1654

L

)

0.2523

L

=

233 K