Question

what mass of a sugar based marshmallow (C12H22O11) should I completely burn over a campfire to get 3.25 grams of carbon?

Answer 1

$C_{12}H_{22}O_{11}+12O_2 \to 12CO_2+11H_2O$

RMM of $CO_2=44$

Moles of 9

mole ratio, $C_{12}H_{22}O_{11}:12CO_2=1:12$

moles of, $C_{12}H_{22}O_{11} = 0.0739$

RMM of , $C_{12}H_{22}O_{11}=342$

mass of , $C_{12}H_{22}O_{11}=342\times 0.0739=25.2738g$