Question

How many kilojoules are released when 1.95 mol

of H202 reacts?

Answer 1

The equivalence of this reaction is:

$2 moles \space of \space H_2O_2 \leftrightarrow 2 moles \space of H_2O \leftrightarrow 1 mole \space of \space O_2 \leftrightarrow -196 KJ$

$1.95\times\frac{-196}{2}=-191.1$