The reaction between calcium carbide (kalburo, CaC₂) and water forms acetylene (C_{2}*H_{2}) and calcium hydroxide [Ca(OH) 2 ].
CaC2+H2O→C2H2+Ca(OH)2
1 mole of CaC2 produce 22.4 litres of acetylene on STP.
1 mole of CaC2→22.4 litres acetylene.
0.2 moles CaC2→0.2×22.4=4.48.litres
Acetylene=4.5 litres.
Therefore,4.5 litres of acetylene is produced.
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