Question

If 28.1 grams of ammonium chloride react to form 8.9 grams of ammonia, how many grams of hydrogen chloride must simultaneously be formed?

Answer 1

NH₄Cl $\rightleftharpoons\>$ NH₃ $+$ HCl

molar mass of NH$_3=17.031g/mol$

Molar mass of HCl $=36.458g/mol$

NH₃ $:$ HCl $=1:1$

$\frac{M_{HCl}}{36.458}=\frac{8.9}{17.031}$

$M_{HCl}=19.0521g$