Answer to Question #295446 in General Chemistry for shamrick

Question

What is the maximum amount in moles of P

2

O

5

P2O5 that can theoretically be made from 112 g

g of O

2

O2 and excess phosphorus?

Answer 1

The reaction that occurs will be

$P_{4(s)} +5\,O_{2(g)} \to 2\, P_2O_{5(g)}$

Using the information provided, we find the maximum amount of P₂O₅ that can be produced:

$112 \, g\,O_2 (\frac{1\,mol\,O_2}{32\,g\,O_2})(\frac{2 \,mol\,P_2O_5}{5\,mol\,O_2})= {1.4\,mol\,P_2O_5}$

In conclusion, 1.4 mol of P₂O₅ are theoretically produced with the oxygen provided as reactant.