Question #295337

1. 19 ^ 42 K - 1 ^ 0 e+

1
Expert's answer
2022-02-09T18:41:02-0500

1942K→2042Ca+−1 0e_{19}^{42}K\to _{20}^{42}Ca+_{-1}^{\>0}e


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United Kingdom #332878 on Nov 2022