Calculate the mass, in grams, of iron(II) sulfate that must be added to a 500-mL volumetric flask in order to prepare 500 mL of a 0.196 M aqueous solution of the salt.
"C= n\/v"
n = 0.196× 0.5= 0.098moles
Mass= 0.098× 152= 14.9g
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