A flask contains a mixture of two gases: NO2 and Ne. If the flask contains 0.768 mol of NO2 and 14.8 g of Ne at a total pressure of 1.17 bar, what is the partial pressure of Ne in the flask (in bar?)
TIP: You don't need the volume of the flask nor the temperature to solve this problem.
n = m / Mr
n(Ne) = m(Ne) / Mr(Ne) = 14.8 g / 20.2 g/mol = 0.732 mol
n(total) = n(Ne) + n(NO2) = 0.732 mol + 0.768 mol = 1.5 mol
"\\chi"(Ne) = n(Ne) / n(total) = 0.732 mol / 1.5 mol = 0.488
PA = "\\chi"A Ptotal
PNe = "\\chi"Ne Ptotal = 0.488 x 1.17bar = 0.57 bar
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