How much table salt should be added to 300 g water to lower its freezing point to -2.00°C?
∆Tf = iKfm
For water, Kf = 1.860 c/kg/mol
i= 2
m= morality of solution.
-2=2x1.86x300÷1000xm
-2= 1.116m
m= 2÷1.116
=0.558
Mass= 0.558×58.5
=32.643
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