Calculate the time for which a current of 0.65A be passed through molten magnesium chloride to get 5g of magnesium (given :Mm(Mg)=24.25gmol-^1
2 moles of electron deposit 24.25g of Magnesium
∴96487×2\therefore96487×2∴96487×2 Coulombs ≡24.25g\equiv24.25g≡24.25g
5g requires
96487×2×524.25=39788.45\frac{96487×2×5}{24.25}=39788.4524.2596487×2×5=39788.45 coulombs
Q=ItQ=ItQ=It
39788.45=0.65×t39788.45=0.65×t39788.45=0.65×t
t=17t=17t=17 hours 131313 seconds
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