Answer to Question #294310 in General Chemistry for Dhanush

Question

Calculate the time for which a current of 0.65A be passed through molten magnesium chloride to get 5g of magnesium (given :Mm(Mg)=24.25gmol-^1

Answer 1

2 moles of electron deposit 24.25g of Magnesium

$\therefore96487×2$ Coulombs $\equiv24.25g$

5g requires

$\frac{96487×2×5}{24.25}=39788.45$ coulombs

$Q=It$

$39788.45=0.65×t$

$t=17$ hours $13$ seconds