If 2.85 moles of H₂ and 1.55 moles of O₂ react how many moles of H₂O can be produced in the reaction below?
2 H₂(g) + O₂(g) → 2 H₂O(g)
2 moles H2 react with 1 mol O2 to form 2 moles of H2O. Therefore the number of moles of O2 needed to react with 2.85 moles H2 is;
Moles of O2= 2.85 moles of H2 * 1 mol of O2/2 moles of H2 = 1.425 moles of O2
1.55 moles of O2 are present before the reaction,
1.55 moles of O2- 1.425 moles of O2= 0.125 moles of O2 remain when the H2 is consumed
H2 is the limiting reactant.
Mol ratio of H2: O2: H2O is 2:1:2 therefore the moles of H2O produced are 2.85 moles.
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