Calculate the pH of a solution which contains 3.7 x10−2 mole of HAc & 4.8 x 10−2 mole of Na Ac in a liter of solution containing pka 9.26.
It is buffer solution,
pH = pKa+ log([NaAc]/[HAc])
= 4.74 + log(4.8×10^-2/3.7×10^-2)
= 4.87
So, pH of solution = 4.87
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