A buffer is prepared using 0.28 M HNO2 and 0.23 M NO2 − . The pKa for HNO2 is 3.34. What is the pH of
this buffer after the addition of 0.05 M HCl?
pH=pKa+log10([A−]/[HA])pH = pKa + log10([A-]/[HA])pH=pKa+log10([A−]/[HA])
= 3.34 + log (0.33/0.23)
= 3.34+ 0.2= 3.54
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