2.0moles of an ideal gas are at a temperature of 130 degree Celsius and a pressure of 2atm, what volume in dm3 will the gas occupy at that temperature
V=2×403.15×8.312.026×105=3307.18×10−5=0.0330718V=\frac{2\times403.15\times8.31}{2.026\times10^5}=3307.18\times10^{-5}=0.0330718V=2.026×1052×403.15×8.31=3307.18×10−5=0.0330718 L
0.0330718 dm3
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