Calculate the mass of pb that will be deposited from an aqueous solution of pb 2 salt by the same quantity of electricity that deposit it 2.70g cu from an aqueous solution of cu 2 salt
Moles of lead deposited = moles of copper = "\\frac{2.70}{63.546}"
Mass of Pb"= \\frac{2.70}{63.546}\u00d7207.2=8.80g"
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