Question

Calculate the mass of pb that will be deposited from an aqueous solution of pb 2 salt by the same quantity of electricity that deposit it 2.70g cu from an aqueous solution of cu 2 salt

Answer 1

Moles of lead deposited = moles of copper = $\frac{2.70}{63.546}$

Mass of Pb$= \frac{2.70}{63.546}×207.2=8.80g$