What is the molar concentration of a solution that has 5.00g of ammonium chloride dissolved in 250.0mL of solution
Answer - Given, mass of ammonium chloride = 5.00 g
Volume = 250.0 mL
Step 1) Moles of ammonium chloride-
Mole = mass ÷ molar mass.
Moles of NH4Cl ="\\frac{5.00 g}{53.49} g\/mol" = 0.0935 moles.
Step 2) Molar Concentration -
We know formula,
Molarity ="\\frac{moles}{volume (L)}"
Volume = 250 mL = 0.250 L
Molarity of NH4Cl ="\\frac{0.0935 moles}{ 0.250 L}" = 0.374 M
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