an organic compound was analysis and found to contain 5.359 gram of carbon , 0.909 gram of hydrogen and three find the empirical and molecular formula if relative mass is 88
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An organic compound was analysed and found to contain 5.359 gram of carbon , 0.909 gram of hydrogen and 3.636 grams of Oxygen. Find the empirical and molecular formula if relative mass is 88.
Solution
Mole ratio
C:H:O "=\\frac {5.359}{12}:\\frac {0.909}{1}:\\frac{3.636}{16}"
"=0.4466:0.909:0.2273"
Dividing by smallest and rounding to nearest whole number
"C:H:O= 2:4:1"
Empirical formula is "C_2H_4O"
Molar mass =44
Formula mass is twice
Molecular Formula= "C_4H_8O_2"
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