Question

an organic compound was analysis and found to contain 5.359 gram of carbon , 0.909 gram of hydrogen and three find the empirical and molecular formula if relative mass is 88

Answer 1

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if the question read:

An organic compound was analysed and found to contain 5.359 gram of carbon , 0.909 gram of hydrogen and 3.636 grams of Oxygen. Find the empirical and molecular formula if relative mass is 88.

Solution

Mole ratio

C:H:O $=\frac {5.359}{12}:\frac {0.909}{1}:\frac{3.636}{16}$

$=0.4466:0.909:0.2273$

Dividing by smallest and rounding to nearest whole number

$C:H:O= 2:4:1$

Empirical formula is $C_2H_4O$

Molar mass =44

Formula mass is twice

Molecular Formula= $C_4H_8O_2$