Question

A 5.00 L of a gas is collected at 100. K and then allowed to

expand to 20.0 L. What must the new temperature be in order

to maintain the same pressure (as required by Charles' Law)?

Answer 1

$\frac{V_1}{T_1}= \frac{V_2}{T_2}$

$\frac{5.00}{100}= \frac{20.0}{T_2}$

$T_2=\frac{100×20.0}{5.00}=400K$