Question

The solubility of magnesium carbonate is 0.0220g in 100ml. Determine the

solubility product.

Answer 1

Molar mass: 84.31 g/mol

Moles$=\frac{0.0220}{84.31}= 0.00026moles$

$100ml = 0.1litres$

Molarity $=\frac {0.00026}{0.1}=0.000026M$