Question

1) Iron can be produced when iron (III) oxide reacts with carbon monoxide gas. /5

Fe2O3(s) + 3CO(g) → 2Fe(s) + 3CO2(g)

11.5 g of Fe2O3 reacts with 2.63 x 1024 molecules of CO. What mass of Fe is expected?

Answer 1

Moles of $Fe_2O_3$ in $11.59$

$\frac{11.59}{159.69}=0.0720$

Moles of $CO$ in $2.63×10^{24}$ molecules

$\frac{2.63×10^{24}}{6.022×10^{23}}=4.3673$

CO is in excess

Moles of Fe produced $=2×0.0720$

$=0.144$

Mass $=0.144×55.845$

$=8.042g$