What volume (mL) of 0.70 M Sodium hydroxide (NaOH) is needed to
neutralize 270 mL of 0.40 M Sulfuric acid (H2SO4)?
2 NaOH + H2SO4 Na2SO4 + 2 H2O
What volume (mL) of 0.70 M Sodium hydroxide (NaOH) is needed to
neutralize 270 mL of 0.40 M Sulfuric acid (H2SO4)?
2 NaOH + H2SO4 + Na2SO4 + 2 H20
=NaOH is equal to 3.09
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