Mg(OH)2 + HCl → MgCl2 + H2O
Determine the number of moles of magnesium chloride produced when 5.0 mol of HCl is combined with excess Mg(OH)2
Balanced equation
Mg(OH)2+2HCl→ MgCl2+2H2OMg(OH)_2+2HCl\to\>MgCl_2+2H_2OMg(OH)2+2HCl→MgCl2+2H2O
Moles of MgCl2=12×MgCl_2=\frac{1}{2}×MgCl2=21× moles of HClHClHCl
=12×5=\frac{1}{2}×5=21×5
=2.5=2.5=2.5 moles
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