Question

What volume will 12.0 g of oxygen gas (O,)

occupy at 25°C and a pressure of 52.7 kPa?

Answer 1

Moles of oxygen gas ( O₂ ) = n = 12 / 32 .

= 0.375 mol.

T = 25 degree celcius = 298 K .

P = 52.7 kpa = ( 52.7 × 1000 ) pa = 52700 pa .

PV = nR T .

V = nRT / P = (0.375 × 8.314 × 298) / (52700)

V = 0.0177 m³ = 17.7 litre